Charlestown, Indiana is located in eastern Clark County at the intersection of State Roads 3, 62, 160 and 403. 

From the I-65 South: Take I-65 Exit 1 which is 10th Street in Jeffersonville, Indiana.  10th Street becomes Indiana State Road 62 which will take you to Charlestown.  In Charlestown, turn left onto State Road 3 (Market Street).  Turn right on High Street and go one block.

From the I-65 North:  Take I-65 Exit 9 which is the exit for Sellersburg, Indiana.  Turn north onto US 31.  After passing through downtown Sellersburg, take State Road 403 northeast to Charlestown.  Turn right onto State Road 3 (Market Street).  Turn left on High Street and go one block.